Optimal. Leaf size=263 \[ \frac{2 \left (7 a (a B+2 A b)+5 b^2 B\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} \text{EllipticF}\left (\frac{1}{2} (c+d x),2\right )}{21 d}+\frac{2 \left (5 a^2 A+6 a b B+3 A b^2\right ) \sin (c+d x) \sqrt{\sec (c+d x)}}{5 d}-\frac{2 \left (5 a^2 A+6 a b B+3 A b^2\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 d}+\frac{2 \left (7 a (a B+2 A b)+5 b^2 B\right ) \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x)}{21 d}+\frac{2 b (9 a B+7 A b) \sin (c+d x) \sec ^{\frac{5}{2}}(c+d x)}{35 d}+\frac{2 b B \sin (c+d x) \sec ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))}{7 d} \]
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Rubi [A] time = 0.37276, antiderivative size = 263, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.212, Rules used = {4026, 4047, 3768, 3771, 2641, 4046, 2639} \[ \frac{2 \left (5 a^2 A+6 a b B+3 A b^2\right ) \sin (c+d x) \sqrt{\sec (c+d x)}}{5 d}-\frac{2 \left (5 a^2 A+6 a b B+3 A b^2\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 d}+\frac{2 \left (7 a (a B+2 A b)+5 b^2 B\right ) \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x)}{21 d}+\frac{2 \left (7 a (a B+2 A b)+5 b^2 B\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{21 d}+\frac{2 b (9 a B+7 A b) \sin (c+d x) \sec ^{\frac{5}{2}}(c+d x)}{35 d}+\frac{2 b B \sin (c+d x) \sec ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))}{7 d} \]
Antiderivative was successfully verified.
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Rule 4026
Rule 4047
Rule 3768
Rule 3771
Rule 2641
Rule 4046
Rule 2639
Rubi steps
\begin{align*} \int \sec ^{\frac{3}{2}}(c+d x) (a+b \sec (c+d x))^2 (A+B \sec (c+d x)) \, dx &=\frac{2 b B \sec ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{7 d}+\frac{2}{7} \int \sec ^{\frac{3}{2}}(c+d x) \left (\frac{1}{2} a (7 a A+3 b B)+\frac{1}{2} \left (5 b^2 B+7 a (2 A b+a B)\right ) \sec (c+d x)+\frac{1}{2} b (7 A b+9 a B) \sec ^2(c+d x)\right ) \, dx\\ &=\frac{2 b B \sec ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{7 d}+\frac{2}{7} \int \sec ^{\frac{3}{2}}(c+d x) \left (\frac{1}{2} a (7 a A+3 b B)+\frac{1}{2} b (7 A b+9 a B) \sec ^2(c+d x)\right ) \, dx+\frac{1}{7} \left (5 b^2 B+7 a (2 A b+a B)\right ) \int \sec ^{\frac{5}{2}}(c+d x) \, dx\\ &=\frac{2 \left (5 b^2 B+7 a (2 A b+a B)\right ) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{21 d}+\frac{2 b (7 A b+9 a B) \sec ^{\frac{5}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b B \sec ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{7 d}+\frac{1}{5} \left (5 a^2 A+3 A b^2+6 a b B\right ) \int \sec ^{\frac{3}{2}}(c+d x) \, dx+\frac{1}{21} \left (5 b^2 B+7 a (2 A b+a B)\right ) \int \sqrt{\sec (c+d x)} \, dx\\ &=\frac{2 \left (5 a^2 A+3 A b^2+6 a b B\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{5 d}+\frac{2 \left (5 b^2 B+7 a (2 A b+a B)\right ) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{21 d}+\frac{2 b (7 A b+9 a B) \sec ^{\frac{5}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b B \sec ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{7 d}+\frac{1}{5} \left (-5 a^2 A-3 A b^2-6 a b B\right ) \int \frac{1}{\sqrt{\sec (c+d x)}} \, dx+\frac{1}{21} \left (\left (5 b^2 B+7 a (2 A b+a B)\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx\\ &=\frac{2 \left (5 b^2 B+7 a (2 A b+a B)\right ) \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{21 d}+\frac{2 \left (5 a^2 A+3 A b^2+6 a b B\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{5 d}+\frac{2 \left (5 b^2 B+7 a (2 A b+a B)\right ) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{21 d}+\frac{2 b (7 A b+9 a B) \sec ^{\frac{5}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b B \sec ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{7 d}+\frac{1}{5} \left (\left (-5 a^2 A-3 A b^2-6 a b B\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \sqrt{\cos (c+d x)} \, dx\\ &=-\frac{2 \left (5 a^2 A+3 A b^2+6 a b B\right ) \sqrt{\cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{5 d}+\frac{2 \left (5 b^2 B+7 a (2 A b+a B)\right ) \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{21 d}+\frac{2 \left (5 a^2 A+3 A b^2+6 a b B\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{5 d}+\frac{2 \left (5 b^2 B+7 a (2 A b+a B)\right ) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{21 d}+\frac{2 b (7 A b+9 a B) \sec ^{\frac{5}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b B \sec ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{7 d}\\ \end{align*}
Mathematica [A] time = 4.60238, size = 221, normalized size = 0.84 \[ \frac{\sec ^{\frac{7}{2}}(c+d x) \left (40 \left (7 a^2 B+14 a A b+5 b^2 B\right ) \cos ^{\frac{7}{2}}(c+d x) \text{EllipticF}\left (\frac{1}{2} (c+d x),2\right )-168 \left (5 a^2 A+6 a b B+3 A b^2\right ) \cos ^{\frac{7}{2}}(c+d x) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )+2 \sin (c+d x) \left (21 \left (15 a^2 A+26 a b B+13 A b^2\right ) \cos (c+d x)+10 \left (7 a^2 B+14 a A b+5 b^2 B\right ) \cos (2 (c+d x))+105 a^2 A \cos (3 (c+d x))+70 a^2 B+140 a A b+126 a b B \cos (3 (c+d x))+63 A b^2 \cos (3 (c+d x))+110 b^2 B\right )\right )}{420 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 7.429, size = 859, normalized size = 3.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (B b^{2} \sec \left (d x + c\right )^{4} + A a^{2} \sec \left (d x + c\right ) +{\left (2 \, B a b + A b^{2}\right )} \sec \left (d x + c\right )^{3} +{\left (B a^{2} + 2 \, A a b\right )} \sec \left (d x + c\right )^{2}\right )} \sqrt{\sec \left (d x + c\right )}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (B \sec \left (d x + c\right ) + A\right )}{\left (b \sec \left (d x + c\right ) + a\right )}^{2} \sec \left (d x + c\right )^{\frac{3}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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